(x-3/2)^2-1/4

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Solution for (x-3/2)^2-1/4 equation: 


x in (-oo:+oo)

(x-(3/2))^2-(1/4) = 0

(x-3/2)^2-1/4 = 0

(4*(x-3/2)^2)/4-1/4 = 0

4*(x-3/2)^2-1 = 0

4*x^2-12*x+8 = 0

4*x^2-12*x+8 = 0

4*(x^2-3*x+2) = 0

x^2-3*x+2 = 0

DELTA = (-3)^2-(1*2*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)+3)/(1*2) or x = (3-1^(1/2))/(1*2)

x = 2 or x = 1

4*(x-1)*(x-2) = 0

(4*(x-1)*(x-2))/4 = 0

(4*(x-1)*(x-2))/4 = 0 // * 4

4*(x-1)*(x-2) = 0

( 4 )

4 = 0

x belongs to the empty set

( x-1 )

x-1 = 0 // + 1

x = 1

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 1, 2 }

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